A) \[10\,\,kHz\]
B) \[7.5\,\,kHz\]
C) \[5\,\,kHz\]
D) \[2.5\,\,kHz\]
Correct Answer: C
Solution :
(c) |
\[\ell =60\,\,cm\] |
\[\rho =2.7\times {{10}^{3}}kg/{{m}^{3}}\] |
\[y=9.27\times {{10}^{10}}Pa\] |
For fundamental frequency\[\frac{\lambda }{2}=\ell \Rightarrow \lambda =2\ell \] |
\[f=\frac{v}{\lambda }\Rightarrow f=\frac{1}{2\ell }\sqrt{\frac{Y}{\rho }}\] |
\[f=\frac{1}{2\times 06}\sqrt{\frac{9.27\times {{10}^{10}}}{2.7\times {{10}^{3}}}}\] |
\[f\approx 5kHz\] |
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