A) 16.6 cm
B) 10.0 cm
C) 20.0 cm
D) 33.3 cm
Correct Answer: C
Solution :
| [c] Speed of wave \[=\text{ }\sqrt{\frac{T}{\mu }}=\text{ }\sqrt{\frac{\frac{8}{5\times {{10}^{-3}}}}{1}}\] |
| \[=\,\,\sqrt{\frac{8\times {{10}^{3}}}{5}}\,=\,40\,m/s\] |
| \[v=F\lambda \] |
| \[\lambda \,\,=\,\,\frac{40}{100\,\,}\,metre\] |
| Distance between two consecutive node |
| \[=\frac{\lambda }{2}=\frac{20}{100}\,\,metre\,\,=\,\,20\,cm\] |
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