A) \[30.5\times {{10}^{4}}\text{ }N\]
B) \[2.50\times {{10}^{4}}\text{ }N\]
C) \[5.15\times {{10}^{3}}\text{ }N\]
D) \[10.2\times {{10}^{2}}\text{ }N\]
Correct Answer: C
Solution :
| (c) |
| \[v=\sqrt{\frac{T}{\mu }}\] |
| \[\Rightarrow \frac{{{v}_{1}}}{{{v}_{2}}}=\sqrt{\frac{{{T}_{1}}}{{{T}_{2}}}}\] \[\Rightarrow \frac{v}{v}\times 2=\sqrt{\frac{2.06\times {{10}^{4}}}{{{T}_{2}}}}\] |
| \[\Rightarrow {{T}_{2}}=\frac{2.06\times {{10}^{4}}}{4}=0.515\times {{10}^{4}}N\] |
| \[\Rightarrow {{T}_{2}}=5.15\times {{10}^{3}}N\] |
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