A) \[5\,m{{s}^{-1}}\]
B) \[20\,m{{s}^{-1}}\]
C) \[10\,m{{s}^{-1}}\]
D) \[15\,m{{s}^{-1}}\]
Correct Answer: D
Solution :
[d] While going up\[(\sin \theta =\tan \theta =\frac{1}{10})\] |
\[W\sin \theta 10+\frac{W}{20}10=P\] |
\[\frac{3W}{2}=P\] |
While going down |
\[\frac{W}{20}v=\frac{P}{2}=\frac{3W}{4}\] \[v=15m/s\] |
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