Consider a force\[\vec{F}=-x\hat{i}+y\hat{j}\]. The work done by this force in moving a particle from point A(1, 0) to B(0, 1) along the line segment is : [JEE MAIN Held on 09-01-2020 Morning] |
(all quantities are in SI units) |
A) 2
B) 1
C) \[\frac{1}{2}\]
D) \[\frac{3}{2}\]
Correct Answer: B
Solution :
[b] \[W=\int{dW=\int{\left( -x\hat{i}+y\hat{j} \right).\left( dx\hat{i}+dy\hat{j} \right)}}\] |
\[W=-\int\limits_{1}^{0}{xdx+}\int\limits_{0}^{1}{ydy}\] |
\[=\frac{1}{2}+\frac{1}{2}=1J\] |
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