The block of mass M moving on the frictionless horizontal surface collides with the spring of spring constant k and compresses it by length L. The maximum momentum of the block after collision is [AIEEE 2005] |
A) \[\sqrt{MK}L\]
B) \[\frac{k{{L}^{2}}}{2M}\]
C) zero
D) \[\frac{M{{L}^{2}}}{k}\]
Correct Answer: A
Solution :
[a] Momentum would be maximum when KE would be maximum and this is the case when total elastic PE is converted into KE. |
According to conservation of energy, |
( for spring) |
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