A) \[-0.5J\]
B) \[-125J\]
C) 1.25J
D) 0.5J
Correct Answer: B
Solution :
[b] The height (traversed by particle while going up is |
\[h=\frac{{{u}^{2}}}{2g}=\frac{25}{2\times 9.8}\] |
Work done by gravity force\[m\,\vec{g}.\vec{h}\] |
\[=0.1\times g\times \frac{25}{2\times 9.8}\cos {{180}^{o}}\] |
(angle between force and displacement is\[180{}^\circ \]) |
\[\therefore \]\[W=-0.1\times \frac{25}{2}=-1.25J\] |
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