JEE Main & Advanced Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति JEE PYQ - Work Energy Power and Collision

  • question_answer
    A body of mass m accelerates uniformly from rest to\[{{v}_{1}}\]in time\[{{t}_{1}}\]. The instantaneous power delivered to the body as a function of time t is [AIEEE 2004]

    A) \[\frac{m{{v}_{1}}t}{{{t}_{1}}}\]

    B) \[\frac{mv_{1}^{2}t}{t_{1}^{2}}\]

    C) \[\frac{m{{v}_{1}}{{t}^{2}}}{{{t}_{1}}}\]

    D) \[\frac{mv_{1}^{2}t}{{{t}_{1}}}\]

    Correct Answer: B

    Solution :

    [b] Let the constant acceleration of body of mass m is a.
    From equation of motion
    \[{{v}_{1}}=0+a{{t}_{1}}\]
    \[\Rightarrow \]\[a=\frac{{{v}_{1}}}{{{t}_{1}}}t\]                                       ...(i)
    At an Instant t, the velocity v of the body
    \[v=0+at\]
    \[v=\frac{{{v}_{1}}}{{{t}_{1}}}t\]                               ...(ii)
    Therefore, instantaneous power
    \[p=Fv=mav\]                           \[(\because F=ma)\]
    \[=m\left( \frac{{{v}_{1}}}{{{t}_{1}}} \right)\times \left( \frac{{{v}_{1}}}{{{t}_{1}}}.t \right)\]   [from Eqs. (i) and (ii)]
    \[=\frac{mv_{1}^{2}t}{t_{1}^{2}}\]


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