A) \[1.5\text{ }m{{s}^{1}}\]
B) \[1.9\text{ }m{{s}^{1}}\]
C) \[1.7\text{ }m{{s}^{1}}\]
D) \[2.0\text{ }m{{s}^{1}}\]
Correct Answer: B
Solution :
| [b] \[{{F}_{total}}=Mg+\text{ }friction\] |
| \[=2000\times 10+4000\] |
| \[=20,000+4000=24000\text{ }N\] |
| \[P=F\times v\] |
| \[60\times 746=24000\times v\] |
| \[\Rightarrow \text{ }v\text{ =}1.86\text{ }m/s\approx 1.9\text{ }m/s\] |
You need to login to perform this action.
You will be redirected in
3 sec
