A) nucleophilic substitution
B) electrophilic substitution
C) elimination
D) electrophilic addition
Correct Answer: C
Solution :
It is an elimination reaction \[C{{H}_{3}}-C{{H}_{2}}OH\xrightarrow[{{H}^{+}}]{\text{conc}\text{.}\,{{H}_{2}}S{{O}_{4}}}C{{H}_{3}}-C{{H}_{2}}\overset{+}{\mathop{O}}\,{{H}_{2}}\] \[C{{H}_{2}}=C{{H}_{2}}\xleftarrow[-{{H}^{+}}]{}C{{H}_{3}}-\overset{+}{\mathop{C}}\,{{H}_{2}}\xleftarrow{-{{H}_{2}}O}\]
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