A) nearer to \[HCl\] end
B) nearer to ammonia end
C) throughout the length of tube
D) at the centre of the tube.
Correct Answer: A
Solution :
Molecular w.t. of \[N{{H}_{3}}=14+3=17\] Molecular w.t. of \[HCl=35.5+1=36.5\] According to Grahams law: \[r\propto \frac{1}{\sqrt{M}}\] Hence, the rate of diffusion will be higher for ammonia as it is lighter than\[HCl.\] Hence, white ring of \[N{{H}_{4}}Cl\] will be formed nearer to \[HCl\] end.You need to login to perform this action.
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