A) \[\text{y}\,\text{kcal}\,\text{mo}{{\text{l}}^{-1}}\]
B) \[z\,\text{kcal}\,\text{mo}{{\text{l}}^{-1}}\]
C) \[\frac{x}{4}\,\text{kcal}\,\text{mo}{{\text{l}}^{-1}}\]
D) \[\frac{y}{2}\,\text{kcal}\,\text{mo}{{\text{l}}^{-1}}\]
Correct Answer: B
Solution :
\[C{{H}_{4}}(g)\xrightarrow{{}}C{{H}_{3}}(g)+H(g);\]\[\Delta H=+z\,kcal\] In this reaction, one C?H bond is breaking hence, \[\Delta H\] represent the bond dissociation energy of C?H bond. Hence C?H bond energy is z kcal.You need to login to perform this action.
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