A) \[1.637\,\overset{\text{o}}{\mathop{\text{A}}}\,\]
B) \[2.637\,\overset{\text{o}}{\mathop{\text{A}}}\,\]
C) \[2.637\,\overset{\text{o}}{\mathop{\text{A}}}\,\]
D) \[0.637\overset{\text{o}}{\mathop{\text{A}}}\,\]
Correct Answer: D
Solution :
Here, inductance \[L=1\,H,\] Applied emf \[({{E}_{rms}})=200\,V\] and frequency \[f=50\,Hz\] The angular frequency \[\omega =2\pi f=2\times 3.14\times 50=314\] Hence value of current \[{{I}_{rms}}=\frac{{{E}_{rms}}}{\omega L}=\frac{200}{314\times 1}=0.637\overset{\text{o}}{\mathop{\text{A}}}\,\]
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