A) \[_{50}S{{n}^{115}}\]
B) \[_{50}S{{n}^{113}}\]
C) \[_{49}S{{n}^{114}}\]
D) \[_{46}S{{n}^{115}}\]
Correct Answer: A
Solution :
We know that when \[\beta \] particle is emitted then atomic number is increased by 1 unit but the mass number remain same. (constant). Hence, \[{}_{48}C{{d}^{115}},\] after the two successive \[\beta \]-decays will give \[{}_{48}C{{d}^{115}}\xrightarrow{-2\beta }{}_{50}S{{n}^{115}}\]
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