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JIPMER Jipmer Medical Solved Paper-1995

  • question_answer
    A certain electric motor wires that carry a             current of 5 A are perpendicular to a magnetic field of 0.8 tesla. The force on each cm of wire is:            

    A)              0.08 N                                     

    B)              0.06 N     

    C)                     0.04 N       

    D)                                     0.02 N

    Correct Answer: C

    Solution :

    Here: Current in the wire \[I=5A\] Length of wire \[l=1\,cm=0.01\text{ }m\] Angle between the wires and magnetic field is \[\theta -90{}^\circ \] Magnetic field B = 0.8 T Now the force on each cm of wires is \[F=IlB\,\sin \theta \] \[=5\times 0.01\times 0.8\,\sin 90{}^\circ \] \[=0.04\,N\]


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