A) \[[Co{{(N{{H}_{3}})}_{4}}S{{O}_{4}}]N{{O}_{2}}\]
B) \[[Cr{{(N{{H}_{3}})}_{5}}S{{O}_{4}}]Cl\]
C) \[[Cr{{(N{{H}_{3}})}_{5}}Cl]S{{O}_{4}}\]
D) both (b) and (c)
Correct Answer: C
Solution :
Only \[[Cr{{(N{{H}_{3}})}_{5}}Cl]\,S{{O}_{4}}\] give sulphate ions\[(SO_{4}^{2-})\] in solution, hence only it will give white precipitate of barium sulphate with\[BaC{{l}_{2}}(aq).\] \[[Cr{{(N{{H}_{3}})}_{5}}Cl]\,S{{O}_{4}}+BaC{{l}_{2}}\xrightarrow{{}}\] \[[Cr{{(N{{H}_{3}})}_{5}}Cl]\,C{{l}_{2}}+\underset{\text{White}}{\mathop{BaS{{O}_{4}}\downarrow }}\,\]
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