A) \[T{{i}^{3+}}\]
B) \[S{{c}^{3+}}\]
C) \[M{{n}^{2+}}\]
D) \[Z{{n}^{2+}}\]
Correct Answer: C
Solution :
The electronic configuration or given ions are: \[T{{i}^{3+}}(19)=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}3{{d}^{1}}\] \[S{{c}^{3+}}(18)=[Ar]\] \[M{{n}^{2+}}(23)=[Ar]\,3{{d}^{5}}\] \[Z{{n}^{2+}}(28)=[Ar]\,3{{d}^{10}}\] As, \[M{{n}^{2+}}\]has maximum number of unpaired electrons (5), hence, it shows maximum magnetic moment.
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