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JIPMER Jipmer Medical Solved Paper-1995

  • question_answer
    If a gas absorbs 200 J of heat and expand by \[500\,c{{m}^{3}}\]against a constant pressure of \[2\times {{10}^{5}}N{{m}^{-2}},\] the change in internal energy is:

    A)  - 300 joule     

    B)                         +100 joule         

    C)         - 100 joule     

    D)         None of these

    Correct Answer: B

    Solution :

    Given that, \[q=200\,J\] \[\Delta V=500\,c{{m}^{3}}=500\times {{10}^{-6}}{{m}^{3}}\] \[P=2\times {{10}^{5}}N{{m}^{-2}}\] According to 1st law of thermodynamics \[\Delta E=q-P\Delta V\] \[=200-(500\times {{10}^{-6}}\times 2\times {{10}^{5}})\] \[=200-100=100\,\text{joule}\]


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