A) \[N{{H}_{3}}\]
B) \[{{C}_{2}}{{H}_{5}}N{{H}_{2}}\]
C) \[{{C}_{6}}{{H}_{5}}N{{H}_{2}}\]
D) all are equally basic
Correct Answer: C
Solution :
Aniline \[({{C}_{6}}{{H}_{5}}N{{H}_{2}})\] is the weakest base. The reason is that in aniline, lone pair of electron is delocalized in benzene ring. Hence, it has lesser electron density on nitrogen atom and hence, do not easily donate electron pair.
You need to login to perform this action.
You will be redirected in
3 sec
