A) electrophilic substitution
B) nucelophilic addition
C) free-radical addition
D) none of the above
Correct Answer: C
Solution :
In Kolbes synthesis of ethane, potassium acetate is electrolysed. \[2C{{H}_{3}}COOK\xrightarrow{\text{electrolysis}}2C{{H}_{3}}CO{{O}^{-}}+2{{K}^{+}}\] At anode: \[2C{{H}_{3}}CO{{O}^{-}}\xrightarrow{{}}2C{{H}_{3}}CO\dot{O}+2{{e}^{-}}\xrightarrow{-C{{O}_{2}}}\] \[2\dot{C}{{H}_{3}}\xrightarrow{{}}\underset{(Ethane)}{\mathop{C{{H}_{3}}-C{{H}_{3}}}}\,\]
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