A)
10\[\Omega \]
B) 20\[\Omega \]
C) 40\[\Omega \]
D) 50\[\Omega \]
Correct Answer: A
Solution :
It is balanced Wheatstone bridge. Hence, C and D are at same potential so CD arm is uneffective. So, \[10\,\Omega \]. resistance in CD arm is uneffective. Now upper arms having resistances \[10\,\Omega \] are connected in series. So their equivalent resistance is \[{{R}_{U}}=10+10=20\,\Omega \] Similarly the equivalent resistance of lower arm which are also connected in series, so \[{{R}_{L}}=10+10=20\,\Omega \] Now \[{{R}_{U}}\] and \[{{R}_{L}}\] are connected in parallel the resistance between AB is \[{{R}_{AB}}=\frac{20\times 20}{20+20}=\frac{400}{40}=10\,\Omega \]
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