A) Mg
B) Ne
C) Na
D) None of these
Correct Answer: A
Solution :
\[{}_{11}N{{a}^{24}}\xrightarrow{{}}{}_{12}M{{g}^{24}}+{}_{-1}{{\beta }^{0}}\] Hence, an isotope of magnesium \[({}_{12}M{{g}^{24}})\]is obtained.You need to login to perform this action.
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