A) 0.63 V
B) - 0.63 V
C) 1.87 V
D) data are insufficient
Correct Answer: C
Solution :
As B has less reduction potential (more electropositive) than that of A. Hence, B will act as anode and A as cathode in the cell. Hence, \[E_{cell}^{\text{o}}={{E}_{cathode}}-{{E}_{anode}}\] \[=(0.62)-(-1.25)=1.87\,volt\]You need to login to perform this action.
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