JIPMER Jipmer Medical Solved Paper-1996

  • question_answer
    The distance between virtual sources in a biprism of an angle a and refractive index \[\mu .\] of the source is placed at \[a\] distance a from it is:

    A)  \[(\mu -1)\alpha \]                        

    B)  \[2(\mu -1)\alpha \,a\]                

    C)  \[2(\mu -1)\alpha \,\]                  

    D)         \[(\mu -1)\alpha \,a\]

    Correct Answer: B

    Solution :

    In the experiment of biprism, the distance between sources is because of deviation produced by two small angled prism. We know that the deviation produced by each prism is \[(\mu -1)\alpha .\] The total deviation is given by\[2(\mu -1)\alpha .\]. Again the separation of sources is given by \[=2(\mu -1)\,\alpha \,a\]


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