A) 0.8 g
B) 0.4 g
C) 0.2 g
D) g
Correct Answer: C
Solution :
When the fireman climbs down a rope with an acceleration a, then the tension of the rope is given by \[T=mg-ma\,(\because \,\text{given}\,{{T}_{\max }}=0.8mg)\] \[m{{a}_{\min }}=mg={{T}_{\max }}\] \[=mg-0.8mg=0.2mg\] or \[m{{a}_{\min }}=0.2\,mg\] Therefore, \[{{a}_{\min }}=0.2g\]
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