JIPMER Jipmer Medical Solved Paper-1996

  • question_answer
    The force acting on a body of mass 10 kg is \[(2\mathbf{\hat{i}}+\mathbf{\hat{j}}\,-\mathbf{\hat{k}})\] N. If the body is initially at rest. The velocity at the end of the 20 sec is:

    A) \[2\sqrt{3}\]                      

    B)         \[3\sqrt{2}\]     

    C)  \[6\sqrt{2}\]                                     

    D)  \[2\sqrt{6}\]

    Correct Answer: D

    Solution :

    Here: mass of the body m = 10 kg Force \[(\overrightarrow{F})=(2\hat{i}+\hat{j}-\hat{k})N\] Initially velocity of the body \[u=0\] time t = 20 sec Acceleration \[\overrightarrow{a}=\frac{\overrightarrow{F}}{m}=\frac{(2\hat{i}+\hat{j}-\hat{k})}{10}\] Hence final velocity of the body \[\overrightarrow{v}=u+\overrightarrow{a}\,t\] \[=0+\left( \frac{2\hat{i}+\hat{j}-\hat{k}}{10} \right)\times 20\] \[=4\hat{i}\,+2\hat{j}-2\hat{k}\] Magnitude of final velocity\[=\sqrt{16+4+4}\] \[=\sqrt{24}=2\sqrt{6}\]


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