JIPMER Jipmer Medical Solved Paper-1996

  • question_answer
    Two soap bubbles are blown. In the first soap bubble the pressure is 2 times that of the other soap bubble. The ratio of their radii will be:

    A)  1 : 4         

    B)                         4 : 1                      

    C)  1 : 2                      

    D)         2 : 1

    Correct Answer: C

    Solution :

    Pressure in the first soap bubble \[({{P}_{1}})=2P\] and pressure in the second bubble \[({{P}_{2}})=P\]from the formula pressure in the bubble \[P=\frac{2T}{R}\]            \[\Rightarrow \]               \[P\propto \frac{1}{R}\] Hence   \[\frac{{{P}_{1}}}{{{P}_{2}}}=\frac{{{R}_{2}}}{{{R}_{1}}}\]              or                \[\frac{2P}{P}=\frac{{{R}_{2}}}{{{R}_{1}}}\] or            \[{{R}_{2}}=\frac{2P}{P}{{R}_{1}}=2{{R}_{1}}\] or            \[{{R}_{1}}:{{R}_{2}}=1:2\]


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