A) IInd orbit
B) IIIrd orbit
C) Ist orbit
D) none of these
Correct Answer: C
Solution :
We know that, \[{{E}_{n}}=-\frac{13.6\,{{Z}^{2}}}{{{n}^{2}}}eV\] \[{{E}_{n}}\propto \frac{1}{{{n}^{2}}}\] Hence, the energy of electron in \[H{{e}^{+}}\] will be maximum in Ist orbit.
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