JIPMER Jipmer Medical Solved Paper-1996

  • question_answer
    The \[\beta -\]decay of \[{}_{11}{{N}^{24}}\]will produce an isotope of:

    A)  Mg                                       

    B)  Ne                        

    C)  Na                        

    D)         None of these

    Correct Answer: A

    Solution :

    \[{}_{11}N{{a}^{24}}\xrightarrow{{}}{}_{12}M{{g}^{24}}+{}_{-1}{{\beta }^{0}}\] Hence, an isotope of magnesium \[({}_{12}M{{g}^{24}})\]is obtained.


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