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JIPMER Jipmer Medical Solved Paper-1996

  • question_answer
    For the transformation, \[{}_{7}{{N}^{14}}+...\xrightarrow{{}}{}_{6}{{C}^{14}}+{}_{1}{{H}^{1}}\] the bombarding particle is:

    A)  proton                                

    B)  neutron             

    C)         deuteron       

    D)         electron

    Correct Answer: B

    Solution :

    The balanced reaction is, \[{}_{7}{{N}^{14}}+{}_{0}{{n}^{1}}\xrightarrow{{}}{}_{6}{{C}^{14}}+{}_{1}{{H}^{1}}\] Hence, the bombarding particle is neutron.


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