A) 4 N
B) 2 N
C) 40 N
D) 20 N
Correct Answer: C
Solution :
Using relation \[v=u+at\] [Here: \[\upsilon =20\,m/s\] \[20=0+0.1a\] \[u=0\] So, \[a=200\,m\text{/}{{s}^{2}}\] \[t=0.1\,\,\sec \]] Again using \[F=ma=0.2\times 200=40\text{ }N\]You need to login to perform this action.
You will be redirected in
3 sec