A) 5
B) 20
C) 80
D) 10
Correct Answer: D
Solution :
From the formula \[F=\frac{YA\,\Delta L}{L}\] \[{{F}_{breaking\,stress}}\propto \frac{Y\pi {{r}^{2}}}{L}\] Hence, \[\frac{5}{{{F}_{2}}}=\frac{\frac{Y\pi {{r}^{2}}}{L}}{\frac{Y\pi (4{{r}^{2}})}{2L}}=\frac{1}{2}\] Therefore, \[{{F}_{2}}=10\,kwt\text{/}{{m}^{2}}\]You need to login to perform this action.
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