A) 1000
B) 2000
C) 1414
D) 707
Correct Answer: B
Solution :
Here: original number of atom\[{{N}_{0}}=2828.\] Half life \[{{T}_{1/2}}=2\,days\] Time of decay = 1 day Number of half lives \[n=\frac{t}{{{t}_{1/2}}}=\frac{1}{2}\] Hence, number of nuclei left after one day \[={{\left( \frac{1}{2} \right)}^{n}}\times \] original number of atom \[={{\left( \frac{1}{2} \right)}^{1/2}}\times 2808=2000\]
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