A) 0.2 mA
B) 0.29 mA
C) 0.35 mA
D) 0.4 mA
Correct Answer: B
Solution :
Here, current gain \[\alpha =0.96\] and emitter current \[{{i}_{e}}=7.2\,mA\] from the relation of current gain \[\alpha =0.96=\frac{{{I}_{c}}}{{{I}_{e}}}=\frac{{{I}_{c}}}{7.2},\] So \[{{I}_{c}}=0.96\times 7.2=6.91\,mA\] Hence the base current \[{{I}_{b}}={{I}_{e}}-{{I}_{c}}=7.2-6.91=0.29\,mA\]You need to login to perform this action.
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