A) 12 ohm
B) 6 ohm
C) 3 ohm
D) 1.2 ohm
Correct Answer: C
Solution :
\[\frac{1}{{{C}_{p}}}=\frac{1}{6}+\frac{1}{6}\] \[=\frac{2}{6}=\frac{1}{3}\] \[{{C}_{p}}=3\,\Omega \]You need to login to perform this action.
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