A) - 2
B) - 1
C) + 2
D) 0
Correct Answer: D
Solution :
Suppose, the oxidation number of Ni is x, then \[4(+1)+x+4\,(-1)=0\] \[x+4-4=0\] \[x=0\] Hence, oxidation state of Ni in \[{{K}_{4}}[Ni{{(CN)}_{4}}]\] is zero.You need to login to perform this action.
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