A) 16
B) 8
C) 4
D) 2
Correct Answer: A
Solution :
Radiation emitted \[{{T}_{1}}=27+273=300\] \[{{T}_{2}}=327+273=600\] \[E\propto {{T}^{4}}\] \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{T_{1}^{4}}{T_{2}^{4}}={{\left( \frac{300}{600} \right)}^{4}}\] \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{1}{16}\] Hence, \[{{E}_{2}}=16{{E}_{1}}\]You need to login to perform this action.
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