A) 2
B) 1
C) 1/2
D) 3/2
Correct Answer: D
Solution :
Given: The periods of pendulum are in the ratio of 3 : 1. From the relation of time period \[T\propto \sqrt{l}\] Suppose the pendulum be in phase after \[n.\] .oscillation of smaller pendulum. Then larger pendulum has made \[\left( n-1 \right)\] oscillation in the same duration it means \[\left( n-1 \right)3=n\times 1\] Hence, \[n=\frac{3}{2}\]You need to login to perform this action.
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