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JIPMER Jipmer Medical Solved Paper-1999

  • question_answer
    Two simple pendulum of lengths in the ratio 9 : 1 are started at time t = 0. They will again be in phase. After shorter pendulum has made n oscillation, where n is:

    A)  2                                            

    B)  1                            

    C)  1/2                       

    D)         3/2

    Correct Answer: D

    Solution :

    Given: The periods of pendulum are in the ratio of 3 : 1. From the relation of time period \[T\propto \sqrt{l}\] Suppose the pendulum be in phase after \[n.\] .oscillation of smaller pendulum. Then larger pendulum has made \[\left( n-1 \right)\] oscillation in the same duration it means \[\left( n-1 \right)3=n\times 1\] Hence,                  \[n=\frac{3}{2}\]


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