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JIPMER Jipmer Medical Solved Paper-1999

  • question_answer
    The oxidation number of nickel in\[{{K}_{4}}[Ni{{(CN)}_{4}}]\] is:

    A)  - 2                                         

    B)  - 1                         

    C)  + 2                        

    D)         0

    Correct Answer: D

    Solution :

    Suppose, the oxidation number of Ni is x, then \[4(+1)+x+4\,(-1)=0\] \[x+4-4=0\] \[x=0\] Hence, oxidation state of Ni in \[{{K}_{4}}[Ni{{(CN)}_{4}}]\] is zero.


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