A) \[N{{a}_{2}}{{O}_{2}}\]
B) \[Cr{{O}_{5}}\]
C) \[{{H}_{2}}S{{O}_{5}}\]
D) \[Pb{{O}_{2}}\]
Correct Answer: D
Solution :
\[Pb{{O}_{2}}\] is not a peroxide. Peroxides contain \[(--\text{O}--\text{O}--)\] linkage.
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