A) 1, 1-dichloro ethane
B) 1, 2-dichloro ethane
C) tetrachloro ethylene
D) mixtures of 1, 2 and 1, 1-dichloro ethane
Correct Answer: A
Solution :
The reaction is as follows (According to Markownikoffs rule) \[\underset{\text{Vinyl}\,\,\text{chloride}}{\mathop{C{{H}_{2}}==CH\cdot Cl}}\,+HCl\xrightarrow{{}}\underset{\text{1,}\,\,\text{1-dichloro}\,\text{ethane}}{\mathop{C{{H}_{3}}--CHC{{l}_{2}}}}\,\]
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