A) \[1.28\times {{10}^{-13}}N,\text{ }1.1\times {{10}^{-4}}m\]
B) \[1.28\times {{10}^{-13~~}}N,\text{ }1.1\text{ }{{10}^{-3}}m\]
C) \[1.28\times {{10}^{-14~}}N,\text{ }1.1\times {{10}^{-3}}m\]
D) \[12.8\times {{10}^{-13~}}N,\text{ }1.1\times {{10}^{-4}}m\]
Correct Answer: A
Solution :
From the relation \[F=qvB=1.6\times {{10}^{-19}}\times 4\times {{10}^{6}}\times 2\times {{10}^{-1}}\] \[=1.28\times {{10}^{-13}}N\] Radius of circular orbit is given by \[r=\frac{m\upsilon }{qB}=\frac{9\times {{10}^{-31}}\times 4\times {{10}^{6}}}{1.6\times {{10}^{-19}}\times 2\times {{10}^{-1}}}\] \[=1.1\times {{10}^{-4}}m\]
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