A) 914 N
B) 91.4 N
C) 9.14 N
D) 0.914 N
Correct Answer: B
Solution :
From the relation for downward force along the slope is given by \[=mg\sin \theta +\mu mg\cos \theta \] \[=mg(\sin \theta +\mu \cos \theta )\] \[=10\times 9.8\,(\sin 30{}^\circ +0.5\times \cos 30{}^\circ )\] \[=10\times 9.8\left( 0.5+\frac{0.5\times \sqrt{3}}{2} \right)\] \[=91.4\,newton\]You need to login to perform this action.
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