A) 80 W
B) 125 W
C) 64 W
D) 100 W
Correct Answer: C
Solution :
From the relation \[P=\frac{{{V}^{2}}}{R}\] \[P=100=\frac{{{(200)}^{2}}}{R}\] so, \[R=\frac{{{(200)}^{2}}}{100}\] ?(i) If it is connected to 169 V then \[{{P}_{1}}=\frac{{{(160)}^{2}}}{R}=\frac{{{(160)}^{2}}}{{{(200)}^{2}}}\times 100\] [from (i)] \[=\frac{256}{4}=64\,watt\]You need to login to perform this action.
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