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JIPMER Jipmer Medical Solved Paper-2000

  • question_answer
    A soap bubble in vacuum has a radius of 3 cm and another soap bubble in vaccum has a radius of 4 cm. If the two bubbles coalesce under isothermal condition, then the radius of the new bubble is :

    A)  4.5cm,                                 

    B)         2.3cm                  

    C)         7 cm                                     

    D)         5 cm

    Correct Answer: D

    Solution :

    The radius of new bubble is given by \[r=\sqrt{r_{1}^{2}+r_{2}^{2}}=\sqrt{{{3}^{2}}+{{4}^{2}}}\]         \[=\sqrt{9+16}=5\,cm\]


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