A) \[2.5\times {{10}^{-17}}J\]
B) \[1.25\,\times {{10}^{-17}}J\]
C) \[2.5\times {{10}^{-19}}J\]
D) \[4.4\times {{10}^{-19}}J\]
Correct Answer: D
Solution :
From the relation \[E=hv=\frac{hc}{\lambda }=\frac{6.62\times {{10}^{-34}}\times 3\times {{10}^{8}}}{450\times {{10}^{-19}}}\] \[=4.4\times {{10}^{-19}}J\]
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