A) \[{{(SiC{{l}_{6}})}^{2-}}\]
B) \[CCl_{6}^{2-}\]
C) \[GeCl_{6}^{2-}\]
D) \[AlCl_{4}^{-}\]
Correct Answer: B
Solution :
\[CCl_{6}^{2-}\] does not exist. The reason is that carbon has no d-orbital, hence it cannot combine with 6 chlorine-atoms. All others (Si, Ge and Al) have d-orbital, hence form the given ions.
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