A) 2
B) 1/2
C) 4
D) 1/4
Correct Answer: A
Solution :
The energy of a photon \[(E)=hv=h\frac{c}{\lambda }\] \[\therefore \] \[E\propto \frac{1}{\lambda }\] \[\therefore \] \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{\lambda }_{2}}}{{{\lambda }_{1}}}\] or \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{6000}{3000}=2\] \[\therefore \] \[{{E}_{1}}:{{E}_{2}}=2:1\]
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