A) 50 minutes
B) 54 minutes
C) 27 minutes
D) 62 minutes
Correct Answer: C
Solution :
For 1st order reaction, \[K=\frac{2.303}{t}\cdot \log \frac{a}{(a-x)}\] \[=\frac{2.303}{90}\times \log \frac{100}{100-90}\] \[=\frac{2.303}{90}\times \log \,10\] \[=\frac{2.303}{90}=0.0256\,{{\min }^{-1}}\] Hence, time required of 50% completion \[(i.e.,\,{{t}_{1/2}})\] \[\Rightarrow \,\,{{t}_{1/2}}=\frac{0.693}{K}=\frac{0.693}{0.256}=27\,\text{minutes}\,(\text{app}\cdot )\]
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